(7 * x^2 - 16) / (3 * x^(2 / 3)) when x = 4/ $\sqrt{7}$

asked by guest
on Nov 26, 2024 at 6:19 am



You asked:

Calculate the value of \(\frac{7 {x}^{2} - 16}{3 {x}^{\frac{2}{3}}}\) when \(x = \frac{4}{\sqrt{7}}\).

MathBot Answer:

\[\frac{7 {x}^{2} - 16}{3 {x}^{\frac{2}{3}}} = \frac{7 {\left( \frac{4}{\sqrt{7}} \right)}^{2} - 16}{3 {\left( \frac{4}{\sqrt{7}} \right)}^{\frac{2}{3}}} = 0\]

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