HCF of 1960 and 6468

asked by guest
on Apr 06, 2025 at 6:11 am



You asked:

Find the greatest common factor of the following numbers: 1960,64681960, 6468.

MathBot Answer:

Method 1:

196196 is the greatest common divisor of 19601960 and 64686468.


The greatest common divisor of two integers is the largest positive integer that divides both integers.

The greatest common divisor of integers bb and aa is written as gcd(b,a)\operatorname{gcd}(b,a).


The greatest common divisor can be computed by Euclid's algorithm, which is based on repeated application of the following fact:gcd(b,a)=gcd(a,r)\operatorname{gcd}(b, a) = \operatorname{gcd}(a, r) where rr is the remainder of bb divided by aa, and 0<ab0 < a \le b.


Euclid's algorithm for computing the greatest common divisor of 19601960 and 64686468:

gcd(6468,1960)=gcd(1960,588)\operatorname{gcd}(6468, 1960) = \operatorname{gcd}(1960, 588), since 588588 is the remainder when 64686468 is divided by 19601960.

gcd(1960,588)=gcd(588,196)\operatorname{gcd}(1960, 588) = \operatorname{gcd}(588, 196), since 196196 is the remainder when 19601960 is divided by 588588.

gcd(588,196)=196\operatorname{gcd}(588, 196) = 196, since 196196 divides 588588.


Method 2:

The greatest common divisor of two integers is the largest positive integer that divides both integers.

The prime factorization of 19601960 is 23×5×722^{3} \times 5 \times 7^{2}.

The prime factorization of 64686468 is 22×3×72×112^{2} \times 3 \times 7^{2} \times 11.

The GCD is the minimum of the prime powers of the two numbers. Find the greatest common divisor by multiplying the prime number powers together, including only the lowest prime number power of those prime factors which are common to both numbers.

gcd(1960,6468)=22×72=196.\text{gcd}(1960, 6468) = 2^{2} \times 7^{2} = 196.