Math Problem Solver

\[ \frac{23}{5} + \frac{28}{3} - \frac{29}{6} = \frac{91}{10} = 9.1 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{23}{5}\), \(\frac{28}{3}\), and \(\frac{-29}{6}\) is \(30\). \[ \begin{aligned} \frac{23}{5} + \frac{28}{3} - \frac{29}{6} &= \frac{23 \cdot 6}{5 \cdot 6} + \frac{28 \cdot 10}{3 \cdot 10} + \frac{-29 \cdot 5}{6 \cdot 5} \\ &= \frac{138 + 280 + -145}{30} \\ &= \frac{273}{30} \\&= \frac{91}{10} \end{aligned} \]