(-1-2x)^5
asked by guest on Mar 28, 2025 at 2:42 pm
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MathBot Answer:
(−1−2x)5=(−2x−1)5\displaystyle {\left( -1 - 2 x \right)}^{5} = \left(- 2 x - 1\right)^{5} (−1−2x)5=(−2x−1)5
(−1−2x)5=−32x5−80x4−80x3−40x2−10x−1{\left( -1 - 2 x \right)}^{5} = - 32 x^{5} - 80 x^{4} - 80 x^{3} - 40 x^{2} - 10 x - 1(−1−2x)5=−32x5−80x4−80x3−40x2−10x−1
(−1−2x)5=−(2x+1)5{\left( -1 - 2 x \right)}^{5} = - \left(2 x + 1\right)^{5}(−1−2x)5=−(2x+1)5
