tan $0,23^{-1}$

asked by guest
on Jul 26, 2024 at 2:31 pm



MathBot Answer:

The sum of \(\tan\left( 0 \right)\) and \({23}^{-1}\) is:

\[\begin{aligned}&=\left(\tan\left( 0 \right)\right) + \left({23}^{-1}\right) \\\\ &= \tan{\left(0 \right)} + \frac{1}{23} \\\\ &= \frac{1}{23} \\\\\end{aligned}\]

The difference of \(\tan\left( 0 \right)\) and \({23}^{-1}\) is:

\[\begin{aligned}&=\left(\tan\left( 0 \right)\right) - \left({23}^{-1}\right) \\\\ &= - \frac{1}{23} + \tan{\left(0 \right)} \\\\ &= - \frac{1}{23} \\\\\end{aligned}\]

The product of \(\tan\left( 0 \right)\) and \({23}^{-1}\) is:

\[\begin{aligned}&=\left(\tan\left( 0 \right)\right) \cdot \left({23}^{-1}\right) \\\\ &= \frac{\tan{\left(0 \right)}}{23} \\\\ &=0 \\\\\end{aligned}\]

The quotient of \(\tan\left( 0 \right)\) and \({23}^{-1}\) is:

\[\begin{aligned}&= \frac{\left(\tan\left( 0 \right)\right)}{\left({23}^{-1}\right)} \\\\ &= 23 \tan{\left(0 \right)} \\\\ &= 0 \\\\\end{aligned}\]

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