Math Problem Solver

\[ \frac{3}{1} + \frac{1}{2} + \frac{1}{3} = \frac{23}{6} = 3.8\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{3}{1}\), \(\frac{1}{2}\), and \(\frac{1}{3}\) is \(6\). \[ \begin{aligned} \frac{3}{1} + \frac{1}{2} + \frac{1}{3} &= \frac{3 \cdot 6}{1 \cdot 6} + \frac{1 \cdot 3}{2 \cdot 3} + \frac{1 \cdot 2}{3 \cdot 2} \\ &= \frac{18 + 3 + 2}{6} \\ &= \frac{23}{6} \end{aligned} \]