log2(p+q)= 3
log2(p-q)=4
You asked:
Solve the system of equations:\[\begin{aligned}\log_{2}\left( p + q \right) &= 3\\\log_{2}\left( p - q \right) &= 4\end{aligned}\]
MathBot Answer:
The system of equations has one solution.
\[p = 12, q = -4\]