6×(3*3−3×6)÷(7*2−40)
asked by guest on Nov 14, 2024 at 9:23 pm
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6(3⋅3−3⋅6)7⋅2−40=2713=2.076923‾\frac{6 \left(3 \cdot 3 - 3 \cdot 6\right)}{7 \cdot 2 - 40} = \frac{27}{13} = 2.\overline{076923}7⋅2−406(3⋅3−3⋅6)=1327=2.076923
6(3⋅3−3⋅6)7⋅2−40=6(9−3⋅6)7⋅2−40=6(9−18)7⋅2−40=6⋅−97⋅2−40=−547⋅2−40=−5414−40=−54−26=2713\begin{aligned}\frac{6 \left(3 \cdot 3 - 3 \cdot 6\right)}{7 \cdot 2 - 40}&=\frac{6 \left(9 - 3 \cdot 6\right)}{7 \cdot 2 - 40}\\&=\frac{6 \left(9 - 18\right)}{7 \cdot 2 - 40}\\&=\frac{6 \cdot -9}{7 \cdot 2 - 40}\\&=\frac{-54}{7 \cdot 2 - 40}\\&=\frac{-54}{14 - 40}\\&=\frac{-54}{-26}\\&=\frac{27}{13}\end{aligned}7⋅2−406(3⋅3−3⋅6)=7⋅2−406(9−3⋅6)=7⋅2−406(9−18)=7⋅2−406⋅−9=7⋅2−40−54=14−40−54=−26−54=1327