6×(3*3−3×6)÷(7*2−40)

asked by guest
on Nov 14, 2024 at 9:23 pm



You asked:

Evaluate the expression: \(\frac{6 \cdot \left(3 \cdot 3 - 3 \cdot 6\right)}{7 \cdot 2 - 40}\)

MathBot Answer:

\[\frac{6 \cdot \left(3 \cdot 3 - 3 \cdot 6\right)}{7 \cdot 2 - 40} = \frac{27}{13} = 2.\overline{076923}\]

\[\begin{aligned}\frac{6 \cdot \left(3 \cdot 3 - 3 \cdot 6\right)}{7 \cdot 2 - 40}& = 6 \cdot \left(3 \cdot 3 - 3 \cdot 6\right) \cdot \frac{1}{7 \cdot 2 - 40}\\& = 6 \cdot \left(9 - 3 \cdot 6\right) \cdot \frac{1}{7 \cdot 2 - 40}\\& = 6 \cdot \left(9 - 18\right) \cdot \frac{1}{7 \cdot 2 - 40}\\& = 6 \cdot -9 \cdot \frac{1}{7 \cdot 2 - 40}\\& = 6 \cdot -9 \cdot \frac{1}{14 - 40}\\& = 6 \cdot \frac{-9}{-26}\\& = 6 \cdot \frac{9}{26}\\& = \frac{27}{13}\end{aligned}\]

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