h(x)=1.5x
determine h-1(x) algebrically
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
h(x)=1.5x
determine h-1(x) algebrically
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.