Math Problem Solver

\[ 4\frac{4}{7} + 2\frac{5}{8} = \frac{403}{56} = 7.196\overline{428571} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{4}{1}\), \(\frac{4}{7}\), \(\frac{2}{1}\), and \(\frac{5}{8}\) is \(56\). \[ \begin{aligned} 4\frac{4}{7} + 2\frac{5}{8} &= \frac{4 \cdot 56}{1 \cdot 56} + \frac{4 \cdot 8}{7 \cdot 8} + \frac{2 \cdot 56}{1 \cdot 56} + \frac{5 \cdot 7}{8 \cdot 7} \\ &= \frac{224 + 32 + 112 + 35}{56} \\ &= \frac{403}{56} \end{aligned} \]