e^(ln(8)-(1/96))72

asked by guest
on Apr 03, 2025 at 2:23 am



You asked:

Evaluate the expression: eln⁡(8)−196⋅72{e}^{\ln\left( 8 \right) - \frac{1}{96}} \cdot 72

MathBot Answer:

eln⁡(8)−196⋅72=576e196≈570.03114177503805603861660135848235{e}^{\ln\left( 8 \right) - \frac{1}{96}} \cdot 72 = \frac{576}{e^{\frac{1}{96}}} \approx 570.03114177503805603861660135848235

eln⁡(8)−196⋅72=elog⁡(8)−196⋅72=e−196+log⁡(8)⋅72=8⋅e−196⋅72=576⋅e−196\begin{aligned}{e}^{\ln\left( 8 \right) - \frac{1}{96}} \cdot 72&=e^{\log{\left(8 \right)} - \frac{1}{96}} \cdot 72\\&=e^{- \frac{1}{96} + \log{\left(8 \right)}} \cdot 72\\&=8 \cdot e^{- \frac{1}{96}} \cdot 72\\&=576 \cdot e^{- \frac{1}{96}}\end{aligned}

ee is Euler's number, a mathematical constant that is approximately 2.718282.71828.

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