y^''-2y^'+y=(Exp^x)/x^2

asked by guest
on Nov 27, 2024 at 3:54 am



Mathbot Says...

I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.

Below are 10 similar questions that I was able to parse.

Similar Questions

y''-2y'+y=e^x/x^3

y''-2y'+y=6e^x/x^4

y''-2y'+y=e^x/x

y''-2y'+y=xlnx, x>0

y"-2y'+y=e^x/x^2

y′′−2y′+y=(x^2+2x+2)/x^3

y''-4y'+13y=x^2e^x

y''-2y'+y=3e^(2x)

y′′−2y′+y=−5e^x

y''-2y'+y=3e^(2x)

+ Submit Question