P(n,r)=n!(nr)! P(n, r) = \frac{n!}{(n-r)!}

Here, n=8 n = 8 and r=3 r = 3 .

P(8,3)=8!(83)!=8×7×61=336 P(8, 3) = \frac{8!}{(8-3)!} = \frac{8 \times 7 \times 6}{1} = 336

asked by guest
on Dec 27, 2024 at 8:23 pm



Mathbot Says...

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