\[ P(n, r) = \frac{n!}{(n-r)!} \]
Here, \( n = 8 \) and \( r = 3 \).
\[ P(8, 3) = \frac{8!}{(8-3)!} = \frac{8 \times 7 \times 6}{1} = 336 \]
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
\[ P(n, r) = \frac{n!}{(n-r)!} \]
Here, \( n = 8 \) and \( r = 3 \).
\[ P(8, 3) = \frac{8!}{(8-3)!} = \frac{8 \times 7 \times 6}{1} = 336 \]
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.