1/6+2/3+1/4

asked by guest
on Nov 16, 2024 at 4:47 am



You asked:

Evaluate the expression: \(\frac{1}{6} + \frac{2}{3} + \frac{1}{4}\)

MathBot Answer:

\[ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = \frac{13}{12} = 1.08\overline{3} \]


The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{6}\), \(\frac{2}{3}\), and \(\frac{1}{4}\) is \(12\). \[ \begin{aligned} \frac{1}{6} + \frac{2}{3} + \frac{1}{4} &= \frac{1 \cdot 2}{6 \cdot 2} + \frac{2 \cdot 4}{3 \cdot 4} + \frac{1 \cdot 3}{4 \cdot 3} \\ &= \frac{2 + 8 + 3}{12} \\ &= \frac{13}{12} \end{aligned} \]