Is (–1, –4) a solution to this system of inequalities?

y ≥ 3x − 1

y ≥ 10x + 6

asked by guest
on Nov 22, 2024 at 11:18 pm



MathBot Answer:

True, $\left( -1, \ -4\right)$ is a solution of $y \geq 3 x - 1 \text{ and } y \geq 10 x + 6$.


$$\begin{gathered}y \geq 3 x - 1\\- 4 \stackrel{?}{\ge} 3 \left(-1\right) - 1\\-4 \ge -4\end{gathered}$$$$\begin{gathered}y \geq 10 x + 6\\- 4 \stackrel{?}{\ge} 10 \left(-1\right) + 6\\-4 \ge -4\end{gathered}$$