x^(3)y'+yx^(2)=-2x^(3)

asked by guest
on Oct 25, 2024 at 4:18 pm



You asked:

Investigate the equation: \({x}^{3} \cdot y^{\prime} + y \cdot {x}^{2} = -\left( 2 \cdot {x}^{3} \right)\).

MathBot Answer:

\[y{\left(x \right)} = - x + \frac{C_{1}}{x}\]

\(C_{1}\) is an arbitrary constant.

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