x^2+2(x^2-1)^0.5-25>=0

asked by guest
on Nov 28, 2024 at 3:31 pm



You asked:

Solve the inequality x2+2(x2−1)0.5−25≥0 {x}^{2} + 2 {\left( {x}^{2} - 1 \right)}^{0.5} - 25 \ge 0 for the variable xx.

MathBot Answer:

x≤−17∧x≥17x \leq - \sqrt{17} \wedge x \geq \sqrt{17}

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