x^2+2(x^2-1)^0.5-25>=0

asked by guest
on Nov 28, 2024 at 3:31 pm



You asked:

Solve the inequality \( {x}^{2} + 2 {\left( {x}^{2} - 1 \right)}^{0.5} - 25 \ge 0 \) for the variable \(x\).

MathBot Answer:

\[x \leq - \sqrt{17} \wedge x \geq \sqrt{17}\]