3b 3^{3}3 + 4b
asked by guest on Apr 03, 2025 at 4:07 am
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MathBot Answer:
3b3+4b=3b3+4b3 {b}^{3} + 4 b = 3 b^{3} + 4 b3b3+4b=3b3+4b
3b3+4b=b(3b2+4)3 {b}^{3} + 4 b = b \left(3 b^{2} + 4\right)3b3+4b=b(3b2+4)