x^2-8x+16
asked by guest on Mar 17, 2025 at 6:34 am
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MathBot Answer:
x2−8x+16=x2−8x+16\displaystyle {x}^{2} - 8 x + 16 = x^{2} - 8 x + 16 x2−8x+16=x2−8x+16
x2−8x+16=(x−4)2{x}^{2} - 8 x + 16 = \left(x - 4\right)^{2}x2−8x+16=(x−4)2