y'-5y=x²

asked by guest
on Jan 18, 2025 at 2:57 am



You asked:

Investigate the equation: \(y^{\prime} - 5 y = {x}^{2}\).

MathBot Answer:

\[y{\left(x \right)} = - \frac{2}{125} - \frac{2 x}{25} - \frac{x^{2}}{5} + C_{1} e^{5 x}\]

\(C_{1}\) is an arbitrary constant.

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).

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