(696.64)+(RB*0.0612)=0.114

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on Apr 06, 2025 at 8:12 am



You asked:

Investigate the equation: 696.64+RB⋅0.0612=0.114696.64 + R B \cdot 0.0612 = 0.114.

MathBot Answer:

The graph of the equation 696.64+RB⋅0.0612=0.114696.64 + R B \cdot 0.0612 = 0.114 is a hyperbola.

The coordinates of its foci are: (−5920471051,5920471051)\left(- \frac{\sqrt{59204710}}{51}, \frac{\sqrt{59204710}}{51}\right) and (5920471051,−5920471051)\left(\frac{\sqrt{59204710}}{51}, - \frac{\sqrt{59204710}}{51}\right).

The coordinates of its vertices are: (−2960235551,2960235551)\left(- \frac{\sqrt{29602355}}{51}, \frac{\sqrt{29602355}}{51}\right) and (2960235551,−2960235551)\left(\frac{\sqrt{29602355}}{51}, - \frac{\sqrt{29602355}}{51}\right).

The asymptotes have equations: −429602355B=0- 4 \sqrt{29602355} B = 0 and 429602355R=04 \sqrt{29602355} R = 0.
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