4^x = 32

asked by guest
on Jan 13, 2025 at 3:34 am



You asked:

Solve the equation \({4}^{x} = 32\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = 2 + \frac{\log{\left(2 \right)}}{\log{\left(4 \right)}} \approx 2.5\]

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