\sum _{n=1}^{\infty \:}\frac{1}{n^4+n^2}

asked by guest
on Oct 05, 2024 at 3:23 pm



You asked:

Evaluate the expression: \(\sum_{n = 1}^{\infty} {\frac{1}{{n}^{4} + {n}^{2}}}\)

MathBot Answer:

\[\sum_{n=1}^{\infty} \frac{1}{n^{4} + n^{2}} = - \frac{\pi}{2 \tanh{\left(\pi \right)}} + \frac{1}{2} + \frac{\pi^{2}}{6}\]