factorize (4c squared+17cd-15d squared)

asked by guest
on Mar 28, 2025 at 6:45 am



You asked:

Factor the expression: 4c2+17cd−15d2\displaystyle 4 {c}^{2} + 17 c d - 15 {d}^{2}

MathBot Answer:

The polynomial factors into the product: 4c2+17cd−15d2=(4c−3d)(c+5d)4 {c}^{2} + 17 c d - 15 {d}^{2} = \left(4 c - 3 d\right) \left(c + 5 d\right)

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