let a and b be subgroup of a finite group g such that a is a subgroup of b show that [g : a] = [g : b][b :a]
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
let a and b be subgroup of a finite group g such that a is a subgroup of b show that [g : a] = [g : b][b :a]
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.