(3x)^2+x
asked by guest on Mar 26, 2025 at 3:53 pm
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MathBot Answer:
(3x)2+x=9x2+x\displaystyle {\left( 3 x \right)}^{2} + x = 9 x^{2} + x (3x)2+x=9x2+x
(3x)2+x=x(9x+1){\left( 3 x \right)}^{2} + x = x \left(9 x + 1\right)(3x)2+x=x(9x+1)