\sqrt{\frac{10^2-2^6}{\frac{3^3-2^3}{2^2}}}-\left(-\frac{3}{7}\right)^2\left(-\frac{3}{7}\right)^{-3}\left(\frac{7}{3}\right)^{-2}
asked by guest
on Nov 25, 2024 at 6:44 pm
You asked:
Evaluate the expression:
2233−23102−26−(−(73))2(−(73))−3(37)−2
MathBot Answer:
2233−23102−26−(−(73))2(−(73))−3(37)−2=73+191219≈3.18156023501816976231508636574592
2233−23102−26−(−(73))2(−(73))−3(37)−2=(102−26)⋅(33−23)⋅2211−(−73)2⋅(−73)31⋅(37)21=(100−26)⋅(33−23)⋅2211−(−73)2⋅(−73)31⋅(37)21=(100−64)⋅(33−23)⋅2211−(−73)2⋅(−73)31⋅(37)21=36⋅(33−23)⋅2211−(−73)2⋅(−73)31⋅(37)21=36⋅(27−23)⋅2211−(−73)2⋅(−73)31⋅(37)21=36⋅(27−8)⋅2211−(−73)2⋅(−73)31⋅(37)21=36⋅19⋅2211−(−73)2⋅(−73)31⋅(37)21=36⋅4191−(−73)2⋅(−73)31⋅(37)21=19144−(−73)2⋅(−73)31⋅(37)21=1912⋅19−(−73)2⋅(−73)31⋅(37)21=1912⋅19−499⋅(−73)31⋅(37)21=1912⋅19−499⋅−27343⋅(37)21=1912⋅19−499⋅−27343⋅499=1912⋅19−−37⋅499=1912⋅19−−73=1912⋅19+73=73+1912⋅19