solve for x: 2^2(x+3)+9-5=32
You asked:
Solve the equation \[{2}^{2} \cdot \left(x + 3\right) + 9 - 5 = 32\] for the unknown \(x\).
MathBot Answer:
The solution is: \[x = 4\]
\[\begin{aligned}{2}^{2} \cdot \left(x + 3\right) + 9 - 5 &= 32\\4 x + 16 &= 32\\4 x &= 16\\x &= 4\end{aligned}\]