$\sqrt{3}/2*sin(2x) - sin^2(x)$

asked by guest
on Dec 28, 2024 at 7:37 am



You asked:

Evaluate the expression: \(\frac{\sqrt{3}}{2} \sin\left( 2 x \right) - {\sin\left( x \right)}^{2}\)

MathBot Answer:

\[\frac{\sqrt{3}}{2} \sin\left( 2 x \right) - {\sin\left( x \right)}^{2} = \frac{\sqrt{3} \sin{\left(2 x \right)}}{2} - \sin^{2}{\left(x \right)}\]