Is (10, 9) a solution to this system of inequalities?

x ≤ 9

x + y ≥ 20

asked by guest
on Mar 29, 2025 at 7:02 pm



MathBot Answer:

False, (10, 9)\left( 10, \ 9\right) is not a solution of x≤9 and x+y≥20x \leq 9 \text{ and } x + y \geq 20.

x≤910≤?910≰9\begin{gathered}x \leq 9\\10 \stackrel{?}{\le} 9\\10 \nleq 9\end{gathered}x+y≥2010+9≥?2019≱20\begin{gathered}x + y \geq 20\\10 + 9 \stackrel{?}{\ge} 20\\19 \ngeq 20\end{gathered}

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