7^ 2x -2*7^x+1=0

asked by guest
on Nov 25, 2024 at 4:40 am



You asked:

Solve the equation 72x−2⋅7x+1=0{7}^{2} x - 2 \cdot {7}^{x} + 1 = 0 for the variable xx.

MathBot Answer:

The 2 solutions to the equation are: x=0.0829329518076124379368287768848800856998607670607−log⁡(7)49log⁡(7)≈0.022210943x=3.94514026874106135968498848271140225356805411235−log⁡(7)49log⁡(7)≈2.0069929\begin{aligned}x &= \frac{0.0829329518076124379368287768848800856998607670607 - \frac{\log{\left(7 \right)}}{49}}{\log{\left(7 \right)}} \approx 0.022210943\\x &= \frac{3.94514026874106135968498848271140225356805411235 - \frac{\log{\left(7 \right)}}{49}}{\log{\left(7 \right)}} \approx 2.0069929\end{aligned}

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