dy/dx when y=ln (x^2+2x/x^2-3x)
You asked:
Calculate the value of \(\frac{d}{dx}\left[y\left( x \right)\right]\) when \(y = \ln\left( {x}^{2} + \frac{2 x}{{x}^{2}} - 3 x \right)\).
MathBot Answer:
\[\frac{d}{d x} y{\left(x \right)} = \frac{2 x - 3 - \frac{2}{x^{2}}}{x^{2} - 3 x + \frac{2 x}{x^{2}}}\]