400m=($v^{2}$)+($w^{2}$/12)

20m=v

4m=w/12

asked by guest
on Nov 24, 2024 at 9:35 pm



You asked:

Solve the system of equations:\[\begin{aligned}400 m &= {v}^{2} + \frac{{w}^{2}}{12}\\20 m &= v\\4 m &= \frac{w}{12}\end{aligned}\]

MathBot Answer:

The system of equations has \(2\) solutions.

\[m = 0, v = 0, w = 0\]\[m = \frac{25}{37}, v = \frac{500}{37}, w = \frac{1200}{37}\]

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