5xy √12x⁵y⁵ + 10x²y² √75x³y³ - 2x³y³ √3xy

asked by guest
on Nov 25, 2024 at 7:47 am



You asked:

Evaluate the expression: 5xy12⋅x5y5+10x2y275⋅x3y3−2x3y33⋅xy5 x y \sqrt{12} \cdot {x}^{5} {y}^{5} + 10 {x}^{2} {y}^{2} \sqrt{75} \cdot {x}^{3} {y}^{3} - 2 {x}^{3} {y}^{3} \sqrt{3} \cdot x y

MathBot Answer:

Evaluated



5xy12⋅x5y5+10x2y275⋅x3y3−2x3y33⋅xy=103x6y6+503x5y5−23x4y4\displaystyle 5 x y \sqrt{12} \cdot {x}^{5} {y}^{5} + 10 {x}^{2} {y}^{2} \sqrt{75} \cdot {x}^{3} {y}^{3} - 2 {x}^{3} {y}^{3} \sqrt{3} \cdot x y = 10 \sqrt{3} x^{6} y^{6} + 50 \sqrt{3} x^{5} y^{5} - 2 \sqrt{3} x^{4} y^{4}

Factored

5xy12⋅x5y5+10x2y275⋅x3y3−2x3y33⋅xy=23x4y4⋅(5x2y2+25xy−1)5 x y \sqrt{12} \cdot {x}^{5} {y}^{5} + 10 {x}^{2} {y}^{2} \sqrt{75} \cdot {x}^{3} {y}^{3} - 2 {x}^{3} {y}^{3} \sqrt{3} \cdot x y = 2 \sqrt{3} x^{4} y^{4} \cdot \left(5 x^{2} y^{2} + 25 x y - 1\right)

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