f(x)=ax^3+bx^2+cx
f(4)=64a+16b+4c=2
f(9)=729a+81b+9c=2
f(13)=2197a+169b+13c=2
find f(52)
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
f(x)=ax^3+bx^2+cx
f(4)=64a+16b+4c=2
f(9)=729a+81b+9c=2
f(13)=2197a+169b+13c=2
find f(52)
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.