\begin{aligned}&15x+31y = -3\\\\&x=-y+3\end{aligned}&15x+31y = -3\\\\&x=-y+3\end{aligned}
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
\begin{aligned}&15x+31y = -3\\\\&x=-y+3\end{aligned}&15x+31y = -3\\\\&x=-y+3\end{aligned}
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.