P(x)= 2x^2+x-5

Q(x)=4x^2+3x-x^4+4+2x^3

R(x)=x^3-x

S(x)=-x-2x^3+8-x^2

S(x) × P(x)=

asked by guest
on Nov 18, 2024 at 8:38 pm



MathBot Answer:

S(x)⋅P(x)=−4x5−4x4+7x3+20x2+13x−40\begin{aligned}S\left( x \right) \cdot P\left( x \right)&=- 4 x^{5} - 4 x^{4} + 7 x^{3} + 20 x^{2} + 13 x - 40\end{aligned}

S(x)⋅P(x)=(8−x−x2−2x3)(−5+x+2x2)S(x)⋅P(x)=−4x5−4x4+7x3+20x2+13x−40\begin{aligned}S\left( x \right) \cdot P\left( x \right)&=\left(8 - x - x^{2} - 2 x^{3}\right) \left(-5 + x + 2 x^{2}\right)\\S\left( x \right) \cdot P\left( x \right)&=- 4 x^{5} - 4 x^{4} + 7 x^{3} + 20 x^{2} + 13 x - 40\\\end{aligned}

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