$\frac{x}{x+3}$ + $\frac{3(2x+1)}{x^2+x-6}$

asked by guest
on Nov 27, 2024 at 2:42 pm



You asked:

Evaluate the expression: \(\frac{x}{x + 3} + \frac{3 \cdot \left(2 x + 1\right)}{{x}^{2} + x - 6}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{x}{x + 3} + \frac{3 \cdot \left(2 x + 1\right)}{{x}^{2} + x - 6} = \frac{x}{x + 3} + \frac{3 \cdot \left(2 x + 1\right)}{x^{2} + x - 6} \)

Expanded

\[\frac{x}{x + 3} + \frac{3 \cdot \left(2 x + 1\right)}{{x}^{2} + x - 6} = \frac{6 x}{x^{2} + x - 6} + \frac{x}{x + 3} + \frac{3}{x^{2} + x - 6}\]

Factored

\[\frac{x}{x + 3} + \frac{3 \cdot \left(2 x + 1\right)}{{x}^{2} + x - 6} = \frac{x + 1}{x - 2}\]

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