(-5)^2-4^2+(1/5)^0/3^2+1

asked by guest
on Mar 15, 2025 at 5:40 pm



You asked:

Evaluate the expression: (−5)2−42+(15)032+1{\left( -5 \right)}^{2} - {4}^{2} + \frac{{\left( \frac{1}{5} \right)}^{0}}{{3}^{2}} + 1

MathBot Answer:

(−5)2−42+(15)032+1=919=10.1‾{\left( -5 \right)}^{2} - {4}^{2} + \frac{{\left( \frac{1}{5} \right)}^{0}}{{3}^{2}} + 1 = \frac{91}{9} = 10.\overline{1}

(−5)2−42+(15)032+1=−52−42+(15)032+1=25−42+(15)032+1=25−16+(15)032+1=9+(15)032+1=9+132+1=9+19+1=829+1=919\begin{aligned}{\left( -5 \right)}^{2} - {4}^{2} + \frac{{\left( \frac{1}{5} \right)}^{0}}{{3}^{2}} + 1&={-5}^{2} - {4}^{2} + \frac{{\left( \frac{1}{5} \right)}^{0}}{{3}^{2}} + 1\\&=25 - {4}^{2} + \frac{{\left( \frac{1}{5} \right)}^{0}}{{3}^{2}} + 1\\&=25 - 16 + \frac{{\left( \frac{1}{5} \right)}^{0}}{{3}^{2}} + 1\\&=9 + \frac{{\left( \frac{1}{5} \right)}^{0}}{{3}^{2}} + 1\\&=9 + \frac{1}{{3}^{2}} + 1\\&=9 + \frac{1}{9} + 1\\&=\frac{82}{9} + 1\\&=\frac{91}{9}\end{aligned}

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