solve this problem

5=5!4!3!

asked by guest
on Feb 01, 2025 at 5:53 am



You asked:

Investigate the equation: 5=5!⋅4!⋅3!5 = 5! \cdot 4! \cdot 3!.

MathBot Answer:

This equation has no unknown quantities, so it is either true or false.

This equation is false because the left-hand side is not equal to the right-hand side.

The left-hand side of the equation is:

55

The right-hand side of the equation is:

5!⋅4!⋅3!=172805! \cdot 4! \cdot 3! = 17280

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