sec^2 x tany dx - sec^2 tan x dy = 0

asked by guest
on Oct 21, 2024 at 8:05 am



You asked:

Investigate the equation: \({\sec\left( x \right)}^{2} \cdot \tan\left( y \right) \cdot d x - {\sec\left( \tan\left( x \right) \right)}^{2} \cdot d y = 0\).

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