2²=16^x find the value of x

asked by guest
on Oct 09, 2024 at 4:16 am



You asked:

Solve the equation \[{2}^{2} = {16}^{x}\] for the unknown \(x\).

MathBot Answer:

The solution is: \[x = \frac{\log{\left(4 \right)}}{\log{\left(16 \right)}} \approx 0.5\]

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