If 2x^2+2y^2-8x-5y-1 = 0 is the equation of a circle then at the point (1,-1) its tangent equation is 4x+9y+5 = 0 in standard form

asked by guest
on Jan 14, 2025 at 7:04 am



Mathbot Says...

I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.


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