-16x/(x^2-4)^2

asked by guest
on Apr 04, 2025 at 3:00 pm



You asked:

Evaluate the expression: −(16x)(x2−4)2\frac{-\left( 16 x \right)}{{\left( {x}^{2} - 4 \right)}^{2}}

MathBot Answer:

Evaluated



−(16x)(x2−4)2=−16x(x2−4)2\displaystyle \frac{-\left( 16 x \right)}{{\left( {x}^{2} - 4 \right)}^{2}} = - \frac{16 x}{\left(x^{2} - 4\right)^{2}}

Expanded

−(16x)(x2−4)2=−16xx4−8x2+16\frac{-\left( 16 x \right)}{{\left( {x}^{2} - 4 \right)}^{2}} = - \frac{16 x}{x^{4} - 8 x^{2} + 16}

Factored

−(16x)(x2−4)2=−16x(x−2)2(x+2)2\frac{-\left( 16 x \right)}{{\left( {x}^{2} - 4 \right)}^{2}} = - \frac{16 x}{\left(x - 2\right)^{2} \left(x + 2\right)^{2}}

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