4 choose 0

asked by guest
on Oct 22, 2024 at 1:36 am



You asked:

Evaluate the expression: \(\operatorname{C}(4, 0)\)

MathBot Answer:

\(\operatorname{C}(4, 0) = 1\)


$$\begin{aligned} \operatorname{C}(4, 0)&=\frac{4!}{0! \left(0 + 4\right)!}\ \ \ \small{\color{grey}\text{using the formula} \operatorname{C}(n, k) = \frac{n!}{k!(n-k)!}}\\&=\frac{1}{0!}\\&=1^{-1}\\&= 1 \end{aligned}$$


\(\operatorname{C}(n, k)\), also written as \(nCk\) or \(n \choose k\), is the combination function. It is often referred to as 'n choose k.' The combination function can be written in factorial form as\(\operatorname{C}(n, k) = \frac{n!}{k!(n-k)!}\)