3(-2r-5)+4=r/2+2

asked by guest
on Apr 04, 2025 at 2:36 pm



You asked:

Solve the equation 3(−(2r)−5)+4=r2+23 \left(-\left( 2 r \right) - 5\right) + 4 = \frac{r}{2} + 2 for the variable rr.

MathBot Answer:

The solution is: r=−2r = -2

−6r−11=r2+2−13r2=13r=−2\begin{aligned}- 6 r - 11 &= \frac{r}{2} + 2\\- \frac{13 r}{2} &= 13\\r &= -2\end{aligned}

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