60516*n^2 - 61008*n + 2481403

factorize

asked by guest
on Nov 25, 2024 at 2:08 pm



You asked:

Factor the expression: \(\displaystyle 60516 {n}^{2} - 61008 n + 2481403\)

MathBot Answer:

Factorization over the real numbers:

\[2481403 \cdot \left(0.0243878160863028 n^{2} - 0.0245860910138337 n + 1\right)\]

Factorization over the complex numbers:

\[60516 \left(n - \left(\frac{62}{123} + \frac{\sqrt{163} i}{2}\right)\right) \left(n - \left(\frac{62}{123} - \frac{\sqrt{163} i}{2}\right)\right)\]


\(i\) is the imaginary unit, defined as \(i^2 = -1\).