17x^2+18d^2-72dx=0 find x
You asked:
Solve the equation \[17 \cdot {x}^{2} + 18 \cdot {d}^{2} - 72 d x = 0\] for the unknown \(x\).
MathBot Answer:
$$\begin{aligned}x &= 3 d \left(\frac{12}{17} - \frac{\sqrt{110}}{17}\right)\\x &= 3 d \left(\frac{\sqrt{110}}{17} + \frac{12}{17}\right)\end{aligned}$$