Math Problem Solver

\[ 1\frac{3}{5} + 1\frac{1}{12} + 3\frac{3}{4} = \frac{193}{30} = 6.4\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{1}\), \(\frac{3}{5}\), \(\frac{1}{1}\), \(\frac{1}{12}\), \(\frac{3}{1}\), and \(\frac{3}{4}\) is \(60\). \[ \begin{aligned} 1\frac{3}{5} + 1\frac{1}{12} + 3\frac{3}{4} &= \frac{1 \cdot 60}{1 \cdot 60} + \frac{3 \cdot 12}{5 \cdot 12} + \frac{1 \cdot 60}{1 \cdot 60} + \frac{1 \cdot 5}{12 \cdot 5} + \frac{3 \cdot 60}{1 \cdot 60} + \frac{3 \cdot 15}{4 \cdot 15} \\ &= \frac{60 + 36 + 60 + 5 + 180 + 45}{60} \\ &= \frac{386}{60} \\&= \frac{193}{30} \end{aligned} \]