-4sin2x=0

asked by guest
on Mar 21, 2025 at 7:13 pm



You asked:

Solve the equation (4sin(2x))=0-\left( 4 \sin\left( 2 x \right) \right) = 0 for the variable xx.

MathBot Answer:

The principal value in π4xπ4- \frac{\pi}{4} \le x \le \frac{\pi}{4} is x0x \approx 0


The real solutions are: x={πn  |  nZ}{3.1415927n  |  nZ}x={π(12+n)  |  nZ}{3.1415927n+1.5707963  |  nZ}\begin{aligned}x &= \left\{\pi n\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{3.1415927 n\; \middle|\; n \in \mathbb{Z}\right\}\\x &= \left\{\pi \left(\frac{1}{2} + n\right)\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{3.1415927 n + 1.5707963\; \middle|\; n \in \mathbb{Z}\right\}\end{aligned}